A planet has double the mass of the earth. It | vedclass

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Question

$m =ho 	imes \frac{4}{3} \pi R ^3$
$R \propto m ^{\frac{1}{3}}(ho=	ext { constan } t)$3
$	ext { weight }= W \propto g \propto \frac{ Gm }{ R

Vedclass · Accepted Answer

$2^{1 / 3} W$

Vedclass · Answer

$m =ho 	imes \frac{4}{3} \pi R ^3$
$R \propto m ^{\frac{1}{3}}(ho=	ext { constan } t)$3
$	ext { weight }= W \propto g \propto \frac{ Gm }{ R ^2}$
$W \propto \frac{ m }{ m ^{2 / 3}} \propto m ^{1 / 3}$
$	ext { So, } W ^1=(2)^{1 / 3}\,W$

A planet has double the mass of the earth. Its average density is equal to the that of the earth. An object weighing $W$ on earth will weigh on that planet:

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