If density of earth increased $4 $ times and its radius become half of what it is, our weight will
Be four times its present value
Be doubled
Remain same
Be halved
A simple pendulum has a time period ${T_1}$ when on the earth’s surface and ${T_2}$ when taken to a height $R$ above the earth’s surface, where $R$ is the radius of the earth. The value of ${T_2}/{T_1}$ is
If density of a planet is double that of the earth and the radius $1.5$ times that of the earth, the acceleration due to gravity on the surface of the planet is ........
The acceleration due to gravity at a height $1\, km$ above the earth is the same as at a depth $d$ below the surface of earth. Then $d\,=$ ......... $km$
If it is assumed that the spinning motion of earth increases, then the weight of a body on equator
Assuming the earth to be a sphere of uniform density the acceleration due to gravity