Value of sqrt[4]{(81)^{-2}} is | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\sqrt[4]{(81)^{-2}}=\sqrt[4]{\left(\frac{1}{81}\right)^{2}}=\sqrt[4]{\left\{\left(\frac{1}{9}\right)^{2}\right\}^{2}}$$=\sqrt[4]{\left(\frac{1}{9}\ri

Vedclass · Accepted Answer

$\frac{1}{9}$

Vedclass · Answer

$\sqrt[4]{(81)^{-2}}=\sqrt[4]{\left(\frac{1}{81}ight)^{2}}=\sqrt[4]{\left\{\left(\frac{1}{9}ight)^{2}ight\}^{2}}$$=\sqrt[4]{\left(\frac{1}{9}ight)^{4}}=\left(\frac{1}{9}ight)^{4 	imes \frac{1}{4}}=\frac{1}{9}$

Hence, $(d)$ is the correct answer.

Value of $\sqrt[4]{(81)^{-2}}$ is

Similar Questions

Between two rational numbers

For each question, select the proper option from four options given, to make the statement true : (Final answer only)

$.............$ is a rational number between $7$ and $8 .$

Express the following in the form $\frac{p}{q},$ where $p$ and $q$ are integers and $q \neq 0$ :

$0 . \overline{001}$

Simplify: $\left[5\left(8^{\frac{1}{3}}+27^{\frac{1}{3}}\right)^{3}\right]^{\frac{1}{4}}$

State whether each of the following statements is true or false

$\sqrt{49}$ is an irrational number.