(N/A) To represent $\sqrt{5.6}$ on the number line,follow these steps:
$1$. Draw a line segment $AB = 5.6 \text{ units}$ on the number line.
$2$. From point $B$,mark a point $C$ such that $BC = 1 \text{ unit}$. Now,$AC = 5.6 + 1 = 6.6 \text{ units}$.
$3$. Find the midpoint $O$ of $AC$. The length $AO = OC = 6.6 / 2 = 3.3 \text{ units}$.
$4$. Draw a semicircle with center $O$ and radius $OA = 3.3 \text{ units}$.
$5$. Draw a perpendicular line at point $B$ to the line $AC$,which intersects the semicircle at point $D$.
$6$. The length $BD$ is equal to $\sqrt{5.6}$.
$7$. With $B$ as the center and $BD$ as the radius,draw an arc on the number line to intersect it at point $E$. The distance $BE$ represents $\sqrt{5.6}$ on the number line.