Express 0.12 overline{3} in the form frac{p}{ | vedclass

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Question

Let $\quad x=0.12 \overline{3}$

so, $10 x=1.2 \overline{3}$

or $10 x-x=1.2 \overline{3}-0.12 \overline{3}=1.2333 \ldots-0.12333 \,...$

or $9

Vedclass · Accepted Answer

$\frac{37}{300}$

Vedclass · Answer

Let $\quad x=0.12 \overline{3}$

so, $10 x=1.2 \overline{3}$

or $10 x-x=1.2 \overline{3}-0.12 \overline{3}=1.2333 \ldots-0.12333 \,...$

or $9 x=1.11$

or $x=\frac{1.11}{9}=\frac{111}{900}$

Therefore, $\quad 0.12 \overline{3}=\frac{111}{900}=\frac{37}{300}$

Express $0.12 \overline{3}$ in the form $\frac{p}{q},$ where $p$ and $q$ are integers and $q \neq 0$

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