Two sides of a parallelogram are along the lines, $x + y = 3$ and $x -y + 3 = 0$. If its diagonals intersect at $(2, 4)$, then one of its vertex is
Two sides of a parallelogram are along the lines, $x + y = 3$ and $x -y + 3 = 0$. If its diagonals intersect at $(2, 4)$, then one of its vertex is
- [JEE MAIN 2019]
- A
$(3, 5)$
- B
$(2, 1)$
- C
$(2, 6)$
- D
$(3, 6)$
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