Two cards are drawn at random and without replacement from a pack of $52$ playing cards. Finds the probability that both the cards are black.

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There are $26$ black cards in a deck of $52$ cards.

Let $P(A)$ be the probability of getting a black card in the first draw.

$\therefore $ $P(A)=\frac{26}{52}=\frac{1}{2}$

Let $\mathrm{P}(\mathrm{B})$ be the probability of getting a black card on second draw. since the card is not replaced,

$\therefore $ $P(B)=\frac{25}{51}$

Thus, probability of getting both the cards black $=\frac{1}{2} \times \frac{25}{51}=\frac{25}{102}$

Similar Questions

Let $X$ and $Y$ are two events such that $P(X \cup Y=P)\,(X \cap Y).$

Statement $1:$ $P(X \cap Y' = P)\,(X' \cap Y = 0).$

Statement $2:$ $P(X) + P(Y = 2)\,P\,(X \cap Y)$

  • [AIEEE 2012]

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