Time (T), velocity (C) and angular momentum ( | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Let mass related as $M \propto \,{T^x}{C^y}{h^z}$
${M^1}{L^0}{T^0} = {\left( T \right)^x}{\left( {{L^1}{T^{ - 1}}} \right)^y}{\left( {{M^1}{L^2}{T^{

Vedclass · Accepted Answer

$\left[ M \right] = \left[ {{T^{ - 1}}\,{C^{ - 2}}\,h} \right]$

Vedclass · Answer

Let mass related as $M \propto \,{T^x}{C^y}{h^z}$
${M^1}{L^0}{T^0} = {\left( T \right)^x}{\left( {{L^1}{T^{ - 1}}} \right)^y}{\left( {{M^1}{L^2}{T^{ - 1}}} \right)^z}$
${M^1}{L^0}{T^0} = {M^z}{L^{y + 2z}} + {T^{x - y - z}}$
$z = 1$
$y + 2z = 0$                      $x - y - z = 0$
$y =  - 2$                           $x + 2 - 1 = 0$
$M = \left[ {{T^{ - 1}}{C^{ - 2}}{h^1}} \right]$

Time $(T)$, velocity $(C)$ and angular momentum $(h)$ are chosen as fundamental quantities instead of mass, length and time. In terms of these, the dimensions of mass would be

Similar Questions

If the buoyant force $F$ acting on an object depends on its volume $V$ immersed in a liquid, the density $\rho$ of the liquid and the acceleration due to gravity $g$. The correct expression for $F$ can be

The value of gravitational acceleration $C.G.S.$ system is $980 \;cm / sec$ ? .find the value of $g$ in $M.K.S$ system?

If the unit of force is $100\,N$, unit of length is $10\,m$ and unit of time is $100\,s$ , what is the unit of mass in this system of units ?

If pressure $P$, velocity $V$ and time $T$ are taken as fundamental physical quantities, the dimensional formula of force is