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(A) Given that mass $(M)$ and angular momentum $(L_{ang} = Mvr)$ are dimensionless,we have:$M = M^0 L^0 T^0$$L_{ang} = M^1 L^2 T^{-1} = M^0 L^0 T^0$Si

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$1, 2, 4$

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(A) Given that mass $(M)$ and angular momentum $(L_{ang} = Mvr)$ are dimensionless,we have:$M = M^0 L^0 T^0$$L_{ang} = M^1 L^2 T^{-1} = M^0 L^0 T^0$Since $M$ is dimensionless,$L^2 T^{-1} = 1$,which implies $T = L^2$.$(1)$ Force $(F = M L T^{-2})$: Since $M$ is dimensionless and $T = L^2$,$F = L^1 (L^2)^{-2} = L^1 L^{-4} = L^{-3}$. (Correct)$(2)$ Energy $(E = M L^2 T^{-2})$: $E = L^2 (L^2)^{-2} = L^2 L^{-4} = L^{-2}$. (Correct)$(3)$ Power $(P = E/T = M L^2 T^{-3})$: $P = L^2 (L^2)^{-3} = L^2 L^{-6} = L^{-4}$. (Incorrect)$(4)$ Linear momentum $(p = M L T^{-1})$: $p = L^1 (L^2)^{-1} = L^1 L^{-2} = L^{-1}$. (Correct)Thus,statements $(1), (2),$ and $(4)$ are correct.

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