The horizontal component of the earth's magnetic field at any place is $0.36 \times 10^{-4} Wb / m ^{2}$. If the angle of dip at that place is $60^{\circ}$, then the value of vertical component of the earth's magnetic field will be ........ $\times 10^{-4}\;W b / m^{2}$
The horizontal component of the earth's magnetic field at any place is $0.36 \times 10^{-4} Wb / m ^{2}$. If the angle of dip at that place is $60^{\circ}$, then the value of vertical component of the earth's magnetic field will be ........ $\times 10^{-4}\;W b / m^{2}$
- [AIIMS 2018]
- A
$0.12$
- B
$0.40$
- C
$0.24$
- D
$0.622$
Similar Questions
The magnetic field of earth is due to
The magnetic field of earth is due to
A compass needle will show which one of the following directions at the earth's magnetic pole
A compass needle will show which one of the following directions at the earth's magnetic pole
A magnet is placed horizontally on ground with its north pole towards the geographic north pole of the earth. The neutral point is obtained
A magnet is placed horizontally on ground with its north pole towards the geographic north pole of the earth. The neutral point is obtained
At magnetic poles of earth, angle of dip is.....$^o$
At magnetic poles of earth, angle of dip is.....$^o$
The pole near the geographic north pole is called ...... . The pole near the geographic south pole is called ...... .
The pole near the geographic north pole is called ...... . The pole near the geographic south pole is called ...... .