The variance of $20$ observations is $5 .$ If each observation is multiplied by $2,$ find the new variance of the resulting observations.
Let the observations be $x_{1}, x_{2}, \ldots, x_{20}$ and $\bar{x}$ be their mean. Given that variance $=5$ and $n=20 .$ We know that
Variance $\left( {{\sigma ^2}} \right) = \frac{1}{n}\sum\limits_{i = 1}^{20} {{{\left( {{x_i} - \bar x} \right)}^2}} $
i.e., $5 = \frac{1}{{20}}\sum\limits_{i = 1}^{20} {{{\left( {{x_i} - \bar x} \right)}^2}} $
or $\sum\limits_{i = 1}^{20} {{{\left( {{x_i} - \bar x} \right)}^2}} = 100$ .......$(1)$
If each observation is multiplied by $2,$ and the new resulting observations are $y_{i},$ then
$y_{i}=2 x_{i} \text { i.e., } x_{i}=\frac{1}{2} y_{i}$
Therefore $\bar y = \frac{1}{n}\sum\limits_{i = 1}^{20} {{y_i}} = \frac{1}{{20}}\sum\limits_{i = 1}^{20} {2{x_i} = 2.\frac{1}{{20}}\sum\limits_{i = 1}^{20} {{x_i}} } $
i.e. $\bar{y}=2 \bar{x} \quad$ or $\quad \bar{x}=\frac{1}{2} \bar{y}$
Substituting the values of $x_{i}$ and $\bar{x}$ in $(1),$ we get
${\sum\limits_{i = 1}^{20} {\left( {\frac{1}{2}{y_i} - \frac{1}{2}\bar y} \right)} ^2} = 100$ i.e., $\sum\limits_{i = 1}^{20} {{{\left( {{y_i} - \bar y} \right)}^2} = 400} $
Thus the variance of new observations $=\frac{1}{20} \times 400=20=2^{2} \times 5$
Mean and variance of a set of $6$ terms is $11$ and $24$ respectively and the mean and variance of another set of $3$ terms is $14$ and $36$ respectively. Then variance of all $9$ terms is equal to
The mean and standard deviation of a group of $100$ observations were found to be $20$ and $3,$ respectively. Later on it was found that three observations were incorrect, which were recorded as $21,21$ and $18 .$ Find the mean and standard deviation if the incorrect observations are omitted.
Suppose values taken by a variable $x$ are such that $a \le {x_i} \le b$, where ${x_i}$ denotes the value of $x$ in the $i^{th}$ case for $i = 1, 2, ...n.$ Then..
Find the mean and variance of the frequency distribution given below:
$\begin{array}{|l|l|l|l|l|} \hline x & 1 \leq x<3 & 3 \leq x<5 & 5 \leq x<7 & 7 \leq x<10 \\ \hline f & 6 & 4 & 5 & 1 \\ \hline \end{array}$
Find the mean and variance for the data
${x_i}$ | $92$ | $93$ | $97$ | $98$ | $102$ | $104$ | $109$ |
${f_i}$ | $3$ | $2$ | $3$ | $2$ | $6$ | $3$ | $3$ |