નિશ્ચાયક $\left| \begin{array}{ccc} 1 & a & b + c \\ 1 & b & c + a \\ 1 & c & a + b \end{array} \right|$ નું મૂલ્ય શું છે?

  • A
    $a + b + c$
  • B
    $(a + b + c)^2$
  • C
    $0$
  • D
    $1 + a + b + c$

Explore More

Similar Questions

જો $\left| \begin{array}{ccc} -2a & a+b & a+c \\ b+a & -2b & b+c \\ c+a & b+c & -2c \end{array} \right| = \alpha (a+b)(b+c)(c+a) \neq 0$ હોય,તો $\alpha$ ની કિંમત શોધો.

સાબિત કરો કે $\left|\begin{array}{ccc}a^{2} & b c & a c+c^{2} \\ a^{2}+a b & b^{2} & a c \\ a b & b^{2}+b c & c^{2}\end{array}\right|=4 a^{2} b^{2} c^{2}$

Difficult
View Solution

નિશ્ચાયકના ગુણધર્મોનો ઉપયોગ કરીને અને વિસ્તરણ કર્યા વગર સાબિત કરો કે:
$\left|\begin{array}{lll}1 & bc & a(b+c) \\ 1 & ca & b(c+a) \\ 1 & ab & c(a+b)\end{array}\right|=0$

જો $\left| \begin{matrix} x - 4 & 2x & 2x \\ 2x & x - 4 & 2x \\ 2x & 2x & x - 4 \end{matrix} \right| = (A + Bx)(x - A)^2$ હોય,તો ક્રમયુક્ત જોડ $(A, B) = $ . . . . .

$\left| {\,\begin{array}{*{20}{c}}1&a&{{a^2} - bc}\\1&b&{{b^2} - ac}\\1&c&{{c^2} - ab}\end{array}\,} \right| = $

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo