The value of electric permittivity of free space is
$9 \times {10^9}\,N{C^2}/{m^2}$
$8.85 \times {10^{ - 12}}\,N{m^2}/{C^2}sec$
$8.85 \times {10^{ - 12}}\,{C^2}/N{m^2}$
$9 \times {10^9}\,{C^2}/N{m^2}$
In hydrogen like system the ratio of coulombian force and gravitational force between an electron and a proton is in the order of:
Two equal negative charge $-q$ are fixed at the fixed points $(0,\,a)$ and $(0,\, - a)$ on the $Y$-axis. A positive charge $Q$ is released from rest at the point $(2a,\,0)$ on the $X$-axis. The charge $Q$ will
Point charges $ + 4q,\, - q$ and $ + 4q$ are kept on the $x - $axis at points $x = 0,\,x = a$ and $x = 2a$ respectively, then
The ratio of the forces between two small spheres with constant charge $(a)$ in air $(b)$ in a medium of dielectric constant $K$ is
Three charges are placed as shown in figure. The magnitude of $q_1$ is $2.00\, \mu C$, but its sign and the value of the charge $q_2$ are not known. Charge $q_3$ is $+4.00\, \mu C$, and the net force on $q_3$ is entirely in the negative $x-$ direction. As per the condition given the sign of $q_1$ and $q_2$ will be