The value of $|z - 5|$ if $z = x + iy$ is:
- A$\sqrt{(x - 5)^2 + y^2}$
- B$x^2 + \sqrt{(y - 5)^2}$
- C$\sqrt{(x - y)^2 + 5^2}$
- D$\sqrt{x^2 + (y - 5)^2}$
Explore More
Similar Questions
If $z = 1 + \cos \theta - i \sin \theta$ and $0 < \theta < \pi$,then $\left[|z - 1|^2 - \frac{|z|^2}{4}\right]^{1/2} =$
If $z_{1} = 2 - i$ and $z_{2} = 1 + i$,find $\left| \frac{z_{1} + z_{2} + 1}{z_{1} - z_{2} + 1} \right|$.
Medium
View SolutionIf $\alpha$ is the modulus of $z_1=4+3 i$,then a point that does not lie in the region represented by $|z-\overline{z_1}| \leq \alpha$ is
The radius of the circle represented by $(1+i)(1+3i)(1+7i) = x+iy$ is $(i = \sqrt{-1})$.
The values of $x$ and $y$ for which the numbers $3 + i{x^2}y$ and ${x^2} + y + 4i$ are conjugate complex can be
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo