$\frac{1}{1! 50!} + \frac{1}{3! 48!} + \frac{1}{5! 46!} + \dots + \frac{1}{49! 2!} + \frac{1}{51! 1!}$ का मान $.............$ है।

  • A
    $\frac{2^{50}}{50!}$
  • B
    $\frac{2^{50}}{51!}$
  • C
    $\frac{2^{51}}{51!}$
  • D
    $\frac{2^{51}}{50!}$

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Similar Questions

मान लीजिए कि $\binom{n}{k}$ का अर्थ ${}^{n}C_{k}$ है और $\left[\begin{array}{c} n \\ k \end{array}\right]=\begin{cases} \binom{n}{k}, & \text{यदि } 0 \leq k \leq n \\ 0, & \text{अन्यथा} \end{cases}$ है। यदि $A_{k}=\sum_{i=0}^{9}\binom{9}{i}\left[\begin{array}{c} 12 \\ 12-k+i \end{array}\right]+\sum_{i=0}^{8}\binom{8}{i}\left[\begin{array}{c} 13 \\ 13-k+i \end{array}\right]$ और $A_{4}-A_{3}=190p$ है,तो $p$ का मान ज्ञात कीजिए:

मान लीजिए $(1 + x)^{10} = \sum_{r=0}^{10} C_r x^r$ और $(1 + x)^7 = \sum_{r=0}^7 d_r x^r$ है। यदि $P = \sum_{r=0}^5 C_{2r}$ और $Q = \sum_{r=0}^3 d_{2r+1}$ है,तो $\frac{P}{2Q}$ का मान ज्ञात कीजिए।

यदि $(1 + x)^n = \sum\limits_{r = 0}^n {{C_r}{x^r}} $ है,तो $\left( {1 + \frac{{{C_1}}}{{{C_0}}}} \right)\left( {1 + \frac{{{C_2}}}{{{C_1}}}} \right)....\left( {1 + \frac{{{C_n}}}{{{C_{n - 1}}}}} \right) = $

Difficult
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योग $\left({ }^{n} C_{1}\right)^{2}+\left({ }^{n} C_{2}\right)^{2}+\left({ }^{n} C_{3}\right)^{2}+\ldots+\left({ }^{n} C_{n}\right)^{2}$ का मान है

$^{4n}C_0 + ^{4n}C_4 + ^{4n}C_8 + ... + ^{4n}C_{4n}$ का मान क्या है?

Difficult
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