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(A) The current gain $\beta$ for a common-emitter configuration is defined as the ratio of the change in collector current $\Delta I_C$ to the change

Vedclass · Accepted Answer

$200$

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(A) The current gain $\beta$ for a common-emitter configuration is defined as the ratio of the change in collector current $\Delta I_C$ to the change in base current $\Delta I_B$ at a constant collector-emitter voltage $V_{CE}$.$\beta = \frac{\Delta I_C}{\Delta I_B}$From the given graph,let us consider the change between two curves,for example,from $I_B = 10 \ \mu A$ to $I_B = 20 \ \mu A$ in the active region.At $I_B = 10 \ \mu A$,the collector current $I_C = 2 \ mA = 2 	imes 10^{-3} \ A$.At $I_B = 20 \ \mu A$,the collector current $I_C = 4 \ mA = 4 	imes 10^{-3} \ A$.Therefore,$\Delta I_C = (4 - 2) \ mA = 2 \ mA = 2 	imes 10^{-3} \ A$.And $\Delta I_B = (20 - 10) \ \mu A = 10 \ \mu A = 10 	imes 10^{-6} \ A$.Now,calculating the current gain:$\beta = \frac{2 	imes 10^{-3}}{10 	imes 10^{-6}} = \frac{2}{10} 	imes 10^3 = 0.2 	imes 1000 = 200$.Thus,the estimated current gain is $200$.

The typical output characteristics curve for a transistor working in the common-emitter configuration is shown in the figure. The estimated current gain from the figure is

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