$A$ common emitter transistor amplifier has a current gain of $50$. If the load resistance is $4 \ k\Omega$ and input resistance is $500 \ \Omega$, the voltage gain of the amplifier is

In the given common emitter transistor circuit,the base current is $I_B = 40 \, \mu A$. Determine the base-emitter voltage $V_{BE}$. (in $, V$)

For a transistor,$\frac{1}{\alpha_{DC}} - \frac{1}{\beta_{DC}}$ is equal to [where $\alpha_{DC}$ and $\beta_{DC}$ are current amplification factors].

The voltage gain and the current amplification factor of a transistor in common emitter configuration are $300$ and $60$ respectively. If the collector resistance is $5 \, k\Omega$, then the base resistance is:

In which of the configurations of a transistor, the power gain is highest?

For a constant collector-emitter voltage of $8\,V$,the collector current of a transistor changed from $4\,mA$ to $6\,mA$,whereas the base current changed from $20\,\mu A$ to $25\,\mu A$. If the transistor is in the active state,the small signal current gain (current amplification factor) will be: