The relation between alpha and beta parameter | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) In a transistor,the emitter current $i_e$ is the sum of the base current $i_b$ and the collector current $i_c$: $i_e = i_b + i_c$ Dividing both si

Vedclass · Accepted Answer

$\alpha = \frac{\beta}{1 + \beta}$

Vedclass · Answer

(B) In a transistor,the emitter current $i_e$ is the sum of the base current $i_b$ and the collector current $i_c$: $i_e = i_b + i_c$ Dividing both sides by $i_c$: $\frac{i_e}{i_c} = \frac{i_b}{i_c} + 1$ We know that $\alpha = \frac{i_c}{i_e}$ (so $\frac{i_e}{i_c} = \frac{1}{\alpha}$) and $\beta = \frac{i_c}{i_b}$ (so $\frac{i_b}{i_c} = \frac{1}{\beta}$). Substituting these values: $\frac{1}{\alpha} = \frac{1}{\beta} + 1$ $\frac{1}{\alpha} = \frac{1 + \beta}{\beta}$ Therefore,$\alpha = \frac{\beta}{1 + \beta}$.

The relation between $\alpha$ and $\beta$ parameters of current gains for a transistor is given by:

Similar Questions

What is the power gain in a $CE$ amplifier,where input resistance is $3 \, k\Omega$ and load resistance is $24 \, k\Omega$,given $\beta = 6$?

For a transistor,the current amplification factor is $\alpha = 0.8$. The transistor is connected in a common emitter configuration. The change in the collector current when the base current changes by $6 \, mA$ is.....$mA$.

In a transistor amplifier, $\beta = 62$, $R_L = 5 \times 10^3 \ \Omega$, and the input resistance is $500 \ \Omega$. The ratio of power gain to voltage gain is .......

The current gain of a common emitter amplifier is $69$. If the emitter current is $7.0\,mA$,the collector current is.....$mA$.

For a transistor to act as a switch,it must be operated in

Vedclass Test Series

Exam Paper Generator

Online Exam Module