When an $N-P-N$ transistor is used as an amplifier,which of the following occurs?

$A$ change of $0.04 \ V$ takes place between the base and the emitter when an input signal is connected to the common emitter transistor amplifier. As a result,a $20 \ \mu A$ change takes place in the base current and a change of $2 \ mA$ takes place in the collector current. The input resistance and $AC$ current gain are:

$A$ transistor cannot be used as an

An $npn$ transistor operates as a common emitter amplifier with a power gain of $10^{6}$. The input circuit resistance is $100\, \Omega$ and the output load resistance is $10\, k\Omega$. The common emitter current gain $\beta$ will be (Round off to the nearest integer).

$A$ transistor having $\alpha=0.8$ is connected in a common-emitter configuration. When the base current changes by $6 \text{ mA}$, the change in collector current is: (in $\text{ mA}$)

The graph between the input voltage $(V_{i})$ and the output voltage $(V_{o})$ of a transistor connected in common emitter configuration is shown in the figure. The active,saturation and cutoff regions of the transistor are respectively