In an $npn$ transistor,$10^{10}$ electrons enter the emitter in $10^{-8}$ second. If $1\%$ of electrons are lost in the base,the fraction of current that enters the collector and the current amplification factor are respectively:

If $ \alpha $-current gain of a transistor is $ 0.98 $,what is the value of $ \beta $-current gain of the transistor?

In a common base circuit of a transistor,the amplification factor is $0.95.$ The base current when the emitter current is $2\,mA,$ is ....$mA$

In a transistor,the collector current is always less than the emitter current because:

$A$ transistor is connected in common emitter circuit configuration. The collector supply voltage is $10 \, V$ and the voltage drop across a resistor of $1000 \, \Omega$ in the collector circuit is $0.6 \, V$. If the current gain factor $(\beta)$ is $24$,then the base current is $.... \, \mu A$. (Round off to the Nearest Integer)

An oscillator is nothing but an amplifier with