અસમતા sqrt{5x-6-x^2}+left( frac{pi }{2}intlim | vedclass

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Question

$\sqrt{5 x-6-x^{2}}+\frac{\pi}{2} \int_{0}^{x} d z>x \int_{0}^{\pi} \sin ^{2} x d x$

$\cos 2 x=\cos 2 n-5 \sin ^{2} x$

$\cos 2 x=1-2 \sin ^{2

Vedclass · Accepted Answer

$(2,3)$

Vedclass · Answer

$\sqrt{5 x-6-x^{2}}+\frac{\pi}{2} \int_{0}^{x} d z>x \int_{0}^{\pi} \sin ^{2} x d x$

$\cos 2 x=\cos 2 n-5 \sin ^{2} x$

$\cos 2 x=1-2 \sin ^{2} x$

$\sin ^{2} x=\frac{1-\cos 2 x}{2}$

$\sqrt{5 x-6-x^{2}+\frac{\pi}{2}|z|_{0}^{x}>x} \mid \frac{1-\cos 2 x}{2} d x$

$\sqrt{5 n-6-n^{2}}+\frac{\pi}{2}(n-0)>x \cdot \frac{n}{2}-\left.\frac{\sin n}{4}\right|_{0} ^{\pi}$

$\sqrt{-\left(x^{2}-5 n+6\right)}+\frac{\pi}{2} \cdot(x)>x\left[\left(\frac{\pi}{2}-\frac{\sin 2 \pi}{4}\right)-\left(\frac{0}{2}-\frac{5 x 10}{4}\right)\right]$

$\sqrt{-\left(x^{2}-5 x+6\right)+\frac{\pi x}{2}}>\frac{\pi x}{2}$

$\sqrt{-\left(x^{2}-3 x-2 x+6\right)}>0$

$-[x(x-3)-2(x-3)]>0$

$(x-2)(x-3)<0$

$x \in(2,3)$

અસમતા $\sqrt{5x-6-x^2}+\left( \frac{\pi }{2}\int\limits_{0}^{x}{dz} \right)>x\int\limits_{0}^{\pi }{{{\sin }^{2}}xdx}$ ની સાચો ઉકેલ ગણ મેળવો.

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