The trajectory of a projectile near the surface of the earth is given as$ y = 2x -9x^2$. If it were launched at an angle $\theta_0$ with speed $v_0$ then $(g = 10\, ms^{-2}$)
${\theta _0} = {\cos ^{ - 1}}\,\left( {\frac{1}{{\sqrt 5 }}} \right)$ and ${v_0} = \frac{5}{3}\,m{s^{ - 1}}$
${\theta _0} = {\cos ^{ - 1}}\,\left( {\frac{2}{{\sqrt 5 }}} \right)$ and ${v_0} = \frac{3}{5}\,m{s^{ - 1}}$
${\theta _0} = {\sin ^{ - 1}}\,\left( {\frac{2}{{\sqrt 5 }}} \right)$ and ${v_0} = \frac{3}{5}\,m{s^{ - 1}}$
${\theta _0} = {\sin ^{ - 1}}\,\left( {\frac{1}{{\sqrt 5 }}} \right)$ and ${v_0} = \frac{5}{3}\,m{s^{ - 1}}$
The velocity of projectile at the intial point $A$ is $\left( {2\hat i + 3\hat j} \right)$ $m/s $ . It's velocity (in $m/s$) at point $B$ is
A ball is thrown upwards at an angle of $60^o$ to the horizontal. It falls on the ground at a distance of $90 \,m$. If the ball is thrown with the same initial velocity at an angle $30^o$, it will fall on the ground at a distance of ........ $m$
At $t = 0$ a projectile is fired from a point $O$(taken as origin) on the ground with a speed of $50\,\, m/s$ at an angle of $53^o$ with the horizontal. It just passes two points $A \& B$ each at height $75 \,\,m$ above horizontal as shown. The horizontal separation between the points $A$ and $B$ is ........ $m$
A particle covers $50\, m$ distance when projected with an initial speed. On the same surface it will cover a distance, when projected with double the initial speed ......... $m$
A ball thrown by a boy is caught by another after $2\ sec$. some distance away in the same level. If the angle of projection is $30^o $, the velocity of projection is ......... $m/s$