The solution set of (5 + 4cos theta )(2cos th | vedclass

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Question

(c) $(5 + 4\cos 	heta )(2\cos 	heta + 1) = 0$

$\cos 	heta = - 5/4$, which is not possible.

$	herefore 2\cos 	heta + 1 = 0$ or $\cos 	heta

Vedclass · Accepted Answer

$\left\{ {\frac{{2\pi }}{3},\frac{{4\pi }}{3}} \right\}$

Vedclass · Answer

(c) $(5 + 4\cos 	heta )(2\cos 	heta + 1) = 0$

$\cos 	heta = - 5/4$, which is not possible.

$	herefore 2\cos 	heta + 1 = 0$ or $\cos 	heta = - 1/2$

==> $	heta = \frac{{2\pi }}{3},\,\,\frac{{4\pi }}{3}.$

Solution set is $\left\{ {\frac{{2\pi }}{3},\,\,\frac{{4\pi }}{3}} ight\} \in [0,\,\,2\pi ]$.

The solution set of $(5 + 4\cos \theta )(2\cos \theta + 1) = 0$ in the interval $[0,\,\,2\pi ]$ is

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