સમીકરણ {log _7}{log _5} (sqrt {{x^2} + 5 + x} | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(c) ${\log _7}{\log _5}(\sqrt {{x^2} + 5 + x} ) = 0 = {\log _7}1$

$ \Rightarrow $ ${({x^2} + 5 + x)^{1/2}} = 5$

$ \Rightarrow $ $({x^2} + x + 5)

Vedclass · Accepted Answer

$x = 4$

Vedclass · Answer

(c) ${\log _7}{\log _5}(\sqrt {{x^2} + 5 + x} ) = 0 = {\log _7}1$

$ \Rightarrow $ ${({x^2} + 5 + x)^{1/2}} = 5$

$ \Rightarrow $ $({x^2} + x + 5) = 25$ $ \Rightarrow $ ${x^2} + x - 20 = 0$

$ \Rightarrow $ $(x - 4)\,(x + 5) = 0$ $ \Rightarrow $$x = \,4,\, - 5$ ==> $x = 4$.

સમીકરણ ${\log _7}{\log _5}$ $(\sqrt {{x^2} + 5 + x} ) = 0$ નો ઉકેલ મેળવો.

Similar Questions

$\sqrt {(\log _{0.5}^24)} = . . $. .

${\log _7}{\log _7}\sqrt {7(\sqrt {7\sqrt 7 } )} = $

અસમતા ${5^{(1/4)(\log _5^2x)}}\, \geqslant \,5{x^{(1/5)(\log _5^x)}}$ નો ઉકેલ ગણ મેળવો

${81^{(1/{{\log }_5}3)}} + {27^{{{\log }_{_9}}36}} + {3^{4/{{\log }_{_7}}9}} = . . . .$