The radioactive nucleus $_7{N^{13}}$decays to $_6{C^{13}}$ through the emission of
The radioactive nucleus $_7{N^{13}}$decays to $_6{C^{13}}$ through the emission of
- A
Neutron
- B
Proton
- C
Electron
- D
Positron
Similar Questions
An element $A$ decays into element $C$ by a two step process :
$A \to B + {\;_2}H{e^4}$
$B \to C + \;2{e^ - }$
Then
An element $A$ decays into element $C$ by a two step process :
$A \to B + {\;_2}H{e^4}$
$B \to C + \;2{e^ - }$
Then
- [AIPMT 1989]
In the following reaction the value of $‘X’$ is $_7{N^{14}}{ + _2}H{e^4}\, \to \,X{ + _1}{H^1}$
In the following reaction the value of $‘X’$ is $_7{N^{14}}{ + _2}H{e^4}\, \to \,X{ + _1}{H^1}$
In nuclear reaction $_2H{e^4}{ + _z}{X^A}{ \to _{z + 2}}{Y^{A + 3}} + A,\;A$ denotes
In nuclear reaction $_2H{e^4}{ + _z}{X^A}{ \to _{z + 2}}{Y^{A + 3}} + A,\;A$ denotes
$\gamma$-decay occurs when
$\gamma$-decay occurs when
When a $_4B{e^9}$ atom is bombarded with $\alpha - $ particles, one of the product of nuclear transmutation is $_6{C^{12}}$. The other is
When a $_4B{e^9}$ atom is bombarded with $\alpha - $ particles, one of the product of nuclear transmutation is $_6{C^{12}}$. The other is