In the following reaction the value of $‘X’$ is $_7{N^{14}}{ + _2}H{e^4}\, \to \,X{ + _1}{H^1}$
$_8{N^{17}}$
$_8{O^{17}}$
$_7{O^{16}}$
$_7{N^{16}}$
${ }_{92} U^{235}$ nucleus absorbs a neutron and disintegrates into ${ }_{54} X e^{139} ,{ }_{38} Sr ^{94}$ and $X$. What will be the product $X$ ?
Beta rays emitted by a radioactive material are
If a heavy nucleus has $N / Z$ ratio higher than that required for stability, then
$_6^{12}C$ absorbs an energetic neutron and emits beta particles. The resulting nucleus is
In the following nuclear rection, $D \stackrel{\alpha}{\longrightarrow} D _{1} \stackrel{\beta-}{\longrightarrow} D _{2} \stackrel{\alpha}{\longrightarrow} D _{3} \stackrel{\gamma}{\longrightarrow} D _{4}$ Mass number of $D$ is $182$ and atomic number is $74$ . Mass number and atomic number of $D _{4}$ respectively will be