An element $A$ decays into element $C$ by a two step process :
$A \to B + {\;_2}H{e^4}$
$B \to C + \;2{e^ - }$
Then
An element $A$ decays into element $C$ by a two step process :
$A \to B + {\;_2}H{e^4}$
$B \to C + \;2{e^ - }$
Then
- [AIPMT 1989]
- A
$A$ and $C$ are isotopes
- B
$A$ and $C$ are isobars
- C
$A$ and $B$ are isotopes
- D
$A$ and $B$ are isobars
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Which of the following will have highest penetrating power
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If $_{92}{U^{238}}$ undergoes successively $8 \alpha$- decays and $6 \beta$- decays, then resulting nucleus is
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- [AIIMS 1996]
In the given reaction $_z{X^A}{ \to _{z + 1}}{Y^A}{ \to _{z - 1}}{K^{A - 4}}{ \to _{z - 1}}{K^{A - 4}}$ Radioactive radiations are emitted in the sequence
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- [AIPMT 1993]
A nucleus with $Z = 92$ emits the following in a sequence: $\alpha ,\,{\beta ^ - },\,{\beta ^ - },\,\alpha ,\alpha ,\alpha ,\alpha ,\alpha ,{\beta ^ - },\,{\beta ^ - },\alpha ,\,{\beta ^ + },\,{\beta ^ + },\,\alpha $. The $Z$ of the resulting nucleus is
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- [AIEEE 2003]
The correct order of ionizing capacity of $\alpha ,\;\beta $ and $\gamma - $ rays is
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