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(A) Let the atomic number of $A$ be $Z$ and the mass number be $A_{mass}$.$1$. In the first step,$A 	o B + {\;_2}He^4$ ($\alpha$ decay):The atomic nu

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$A$ and $C$ are isotopes

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(A) Let the atomic number of $A$ be $Z$ and the mass number be $A_{mass}$.$1$. In the first step,$A 	o B + {\;_2}He^4$ ($\alpha$ decay):The atomic number of $B$ becomes $Z - 2$ and the mass number becomes $A_{mass} - 4$.$2$. In the second step,$B 	o C + 2e^-$ ($\beta$ decay):Since one $\beta$ decay increases the atomic number by $1$,two $\beta$ decays increase the atomic number by $2$.Therefore,the atomic number of $C$ becomes $(Z - 2) + 2 = Z$.Since $A$ and $C$ have the same atomic number $Z$ but different mass numbers ($A_{mass}$ and $A_{mass} - 4$),they are isotopes.

An element $A$ decays into element $C$ by a two-step process:
$A \to B + {\;_2}He^4$
$B \to C + 2e^-$
Then:

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An element $A$ decays into element $C$ by a two-step process:$A \to B + {\;_2}He^4$$B \to C + 2e^-$Then: