When a $_4B{e^9}$ atom is bombarded with $\alpha - $ particles, one of the product of nuclear transmutation is $_6{C^{12}}$. The other is
When a $_4B{e^9}$ atom is bombarded with $\alpha - $ particles, one of the product of nuclear transmutation is $_6{C^{12}}$. The other is
- A
$_{ - 1}{e^0}$
- B
$X - $
- C
$_1{D^2}$
- D
$_0{n^1}$
Similar Questions
A free neutron decays into a proton, an electron and
A free neutron decays into a proton, an electron and
In which of the following nuclear reactions, the product is incorrectly matched ?
In which of the following nuclear reactions, the product is incorrectly matched ?
Match List $I$ of the nuclear processes with List $II$ containing parent nucleus and one of the end products of each process and then select the correct answer using the codes given below the lists :
List $I$
List $II$
$P.$ $\quad$ Alpha decay
$1.$ $\quad{ }_8^{15} 0 \rightarrow{ }_7^{15} N +\ldots \ldots$.
$Q.$ $\quad$ $\beta^{+}$decay
$2.$ $\quad{ }_{92}^{238} U \rightarrow{ }_{90}^{234} Th +\ldots \ldots$.
$R.$ $\quad$Fission
$3.$ $\quad{ }_{83}^{185} Bi \rightarrow{ }_{82}^{184} Pb +\ldots \ldots$.
$S.$ $\quad$Proton emission
$4.$ $\quad{ }_{94}^{239} Pu \rightarrow{ }_{57}^{140} La +\ldots \ldots$.
Codes: $ \quad \quad P \quad Q \quad R \quad S $
Match List $I$ of the nuclear processes with List $II$ containing parent nucleus and one of the end products of each process and then select the correct answer using the codes given below the lists :
| List $I$ | List $II$ |
| $P.$ $\quad$ Alpha decay | $1.$ $\quad{ }_8^{15} 0 \rightarrow{ }_7^{15} N +\ldots \ldots$. |
| $Q.$ $\quad$ $\beta^{+}$decay | $2.$ $\quad{ }_{92}^{238} U \rightarrow{ }_{90}^{234} Th +\ldots \ldots$. |
| $R.$ $\quad$Fission | $3.$ $\quad{ }_{83}^{185} Bi \rightarrow{ }_{82}^{184} Pb +\ldots \ldots$. |
| $S.$ $\quad$Proton emission | $4.$ $\quad{ }_{94}^{239} Pu \rightarrow{ }_{57}^{140} La +\ldots \ldots$. |
Codes: $ \quad \quad P \quad Q \quad R \quad S $
- [IIT 2013]
${ }_{92} U^{235}$ nucleus absorbs a neutron and disintegrates into ${ }_{54} X e^{139} ,{ }_{38} Sr ^{94}$ and $X$. What will be the product $X$ ?
${ }_{92} U^{235}$ nucleus absorbs a neutron and disintegrates into ${ }_{54} X e^{139} ,{ }_{38} Sr ^{94}$ and $X$. What will be the product $X$ ?
In the disintegration series
$_{92}^{238}U\xrightarrow{\alpha }x\xrightarrow{\beta }_Z^AY$
The value of $Z$ and $A$ respectively will be
In the disintegration series
$_{92}^{238}U\xrightarrow{\alpha }x\xrightarrow{\beta }_Z^AY$
The value of $Z$ and $A$ respectively will be