$\frac{6x^4 + 5x^3 + x^2 + 5x + 2}{1 + 5x + 6x^2}$ का आंशिक भिन्न =

  • A
    $x^2 + \frac{1}{1 + 2x} + \frac{1}{1 + 3x}$
  • B
    $x^2 - \frac{1}{1 + 2x} + \frac{1}{1 + 3x}$
  • C
    $x^2 + \frac{1}{1 + 2x} - \frac{1}{1 - 3x}$
  • D
    इनमें से कोई नहीं

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यदि $\frac{2x}{x^3 - 1} = \frac{A}{x - 1} + \frac{Bx + C}{x^2 + x + 1}$ हो,तब:

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यदि $\frac{x^2-3x+2}{(x-4)(x-3)^2}=\frac{A}{x-4}+\frac{B}{x-3}+\frac{C}{(x-3)^2}$ है,तो $A+B+C=$

यदि $\frac{2x+1}{(x-1)^2(x^2+1)}=\frac{A}{x-1}+\frac{B}{(x-1)^2}+\frac{Cx+D}{x^2+1}$ है,तो $A+B+C+D=$

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