The origin and the points where the line $L_1$ intersects the $x$-axis and $y$-axis are vertices of a right-angled triangle $T$ whose area is $8$. Also,the line $L_1$ is perpendicular to the line $L_2: 4x - y = 3$. Then,the perimeter of triangle $T$ is:

  • A
    $10 + \sqrt{68}$
  • B
    $8 + \sqrt{32}$
  • C
    $17 + \sqrt{257}$
  • D
    $4\sqrt{2} + 4$

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