Given three points P, Q, R with P(5, 3) and R | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

Equation of $RQ$ is $x-2y=2$       .....(1)

at $Y=0$,$X=2$ $[R (2,0)]$

as $PQ$ is parallel to $x,y$-coordinates of $Q$ is al

Vedclass · Accepted Answer

$2x-5y = 0$

Vedclass · Answer

Equation of $RQ$ is $x-2y=2$       .....(1)

at $Y=0$,$X=2$ $[R (2,0)]$

as $PQ$ is parallel to $x,y$-coordinates of $Q$ is also $3$

putting value of $y$ in equation $(1)$, we get $Q(8,3)$

Centroid of $\Delta PQR = \left( {\frac{{8 + 5 + 2}}{3},\frac{{3 + 3}}{3}} \right)$

$=(5,2)$

Only $(2x - 5y = 0)$ satisfy the given coordinates.

Given three points $P, Q, R$ with $P(5, 3)$ and $R$ lies on the $x-$ axis. If equation of $RQ$ is $x - 2y = 2$ and $PQ$ is parallel to the $x-$ axis, then the centroid of $\Delta PQR$ lies on the line

Similar Questions

A point $P$ moves on the line $2x -3y + 4 = 0$. If $Q(1, 4)$ and $R(3, -2)$ are fixed points, then the locus of the centroid of $\Delta PQR$ is a line

If in a parallelogram $ABDC$, the coordinates of $A, B$ and $C$ are respectively $(1, 2), (3, 4)$ and $(2, 5)$, then the equation of the diagonal $AD$ is

Let $A B C$ be a triangle formed by the lines $7 x-6 y+3=0, x+2 y-31=0$ and $9 x-2 y-19=0$, Let the point $( h , k )$ be the image of the centroid of $\Delta A B C$ in the line $3 x+6 y-53=0$. Then $h^2+k^2+h k$ is equal to

Two mutually perpendicular straight lines through the origin from an isosceles triangle with the line $2x + y = 5$ . Then the area of the triangle is :

A square of side a lies above the $x$ -axis and has one vertex at the origin. The side passing through the origin makes an angle $\alpha ,(0 < \alpha < \frac{\pi }{4})$ with the positive direction of $x$-axis. The equation of its diagonal not passing through the origin is