The number of values of x for which sin 2x + | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given the equation $\sin 2x + \cos 4x = 2$.We know that the maximum value of $\sin 	heta$ is $1$ and the maximum value of $\cos 	heta$ is $1$.Fo

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(A) Given the equation $\sin 2x + \cos 4x = 2$.We know that the maximum value of $\sin 	heta$ is $1$ and the maximum value of $\cos 	heta$ is $1$.For the sum to be $2$,both terms must simultaneously take their maximum values:$\sin 2x = 1$ and $\cos 4x = 1$.Using the identity $\cos 4x = 1 - 2\sin^2 2x$,we substitute $\sin 2x = 1$ into the equation:$\cos 4x = 1 - 2(1)^2 = 1 - 2 = -1$.However,we require $\cos 4x = 1$.Since $-1 
eq 1$,there are no values of $x$ that satisfy the equation.Thus,the number of values of $x$ is $0$.

The number of values of $x$ for which $\sin 2x + \cos 4x = 2$ is

Similar Questions

The number of solutions of the equation $\sqrt[3]{\sin \theta - 1} + \sqrt[3]{\sin \theta} + \sqrt[3]{\sin \theta + 1} = 0$ in the interval $[0, 4\pi]$ is:

The number of solutions of $8 \cos x = x$ will be:

The general solution of the equation $3 \sec^2 \theta = 2 \operatorname{cosec} \theta$ is

The set of solutions of the equation $(\sqrt{3}-1) \sin \theta+(\sqrt{3}+1) \cos \theta=2$ is

The number of values of $x$ in the interval $[0, 5\pi]$ satisfying the equation $3 \sin^2 x - 7 \sin x + 2 = 0$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module