The number obtained on rationalizing the deno | vedclass

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Question

$\frac{1}{7-\sqrt{2}}=\frac{1}{7-\sqrt{2}} 	imes \frac{7+\sqrt{2}}{7+\sqrt{2}}=\frac{7+\sqrt{2}}{(7)^{2}-(\sqrt{2})^{2}}=\frac{7+\sqrt{2}}{49-2}=\fra

Vedclass · Accepted Answer

$\frac{7+\sqrt{2}}{47}$

Vedclass · Answer

$\frac{1}{7-\sqrt{2}}=\frac{1}{7-\sqrt{2}} 	imes \frac{7+\sqrt{2}}{7+\sqrt{2}}=\frac{7+\sqrt{2}}{(7)^{2}-(\sqrt{2})^{2}}=\frac{7+\sqrt{2}}{49-2}=\frac{7+\sqrt{2}}{47}$

Hence, $(a)$ is the correct answer.

The number obtained on rationalizing the denominator of $\frac{1}{7-\sqrt{2}}$ is

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