If sqrt{2}=1.414, sqrt{3}=1.732, then find th | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

We have $\frac{4}{3 \sqrt{3}-2 \sqrt{2}}+\frac{3}{3 \sqrt{3}+2 \sqrt{2}}$

$=\frac{4 \sqrt{3}+2 \sqrt{2}+3(3 \sqrt{3}-2 \sqrt{2})}{(3 \sqrt{3}-2 \sq

Vedclass · Accepted Answer

$2.063$

Vedclass · Answer

We have $\frac{4}{3 \sqrt{3}-2 \sqrt{2}}+\frac{3}{3 \sqrt{3}+2 \sqrt{2}}$

$=\frac{4 \sqrt{3}+2 \sqrt{2}+3(3 \sqrt{3}-2 \sqrt{2})}{(3 \sqrt{3}-2 \sqrt{2})(3 \sqrt{3}+2 \sqrt{2})}$

$=\frac{12 \sqrt{3}+8 \sqrt{2}+9 \sqrt{3}-6 \sqrt{2}}{(3 \sqrt{3})^{2}-(2 \sqrt{2})^{2}}=\frac{21 \sqrt{3}+2 \sqrt{2}}{27-8}$

$=\frac{21 \sqrt{3}+2 \sqrt{2}}{19}=\frac{21(1.732)+2(1.414)}{19}$

$=\frac{36.372+2.828}{19}=2.063$

If $\sqrt{2}=1.414, \sqrt{3}=1.732,$ then find the value of $\frac{4}{3 \cdot \sqrt{3}-2 \cdot \sqrt{2}}+\frac{3}{3 \cdot \sqrt{3}+2 \cdot \sqrt{2}}$

Similar Questions

Express $0 . \overline{4}$ in the form $\frac{p}{q} ;$ where $p$ and $q$ are integers and $q \neq 0$

Simplify: $\frac{7 \sqrt{3}}{\sqrt{10}+\sqrt{3}}-\frac{2 \sqrt{5}}{\sqrt{6}+\sqrt{5}}-\frac{3 \sqrt{2}}{\sqrt{15}+3 \sqrt{2}}$

Find three different irrational numbers between the rational numbers $\frac{1}{4}$ and $\frac{4}{5}$.

Locate $\sqrt{5}, \sqrt{10}$ and $\sqrt{17}$ on the number line.

Find three rational numbers between

$0.1$ and $0.11$