The negation of sim s vee (sim r wedge s) is | vedclass

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(A) Let the given expression be $P = \sim s \vee (\sim r \wedge s)$.We want to find the negation $\sim P = \sim (\sim s \vee (\sim r \wedge s))$.Using

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$s \wedge r$

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(A) Let the given expression be $P = \sim s \vee (\sim r \wedge s)$.We want to find the negation $\sim P = \sim (\sim s \vee (\sim r \wedge s))$.Using De Morgan's Law,$\sim (A \vee B) = \sim A \wedge \sim B$,we get:$\sim P = \sim (\sim s) \wedge \sim (\sim r \wedge s)$.This simplifies to $s \wedge (\sim (\sim r) \vee \sim s)$ by applying De Morgan's Law again.So,$\sim P = s \wedge (r \vee \sim s)$.Using the Distributive Law,$A \wedge (B \vee C) = (A \wedge B) \vee (A \wedge C)$,we get:$\sim P = (s \wedge r) \vee (s \wedge \sim s)$.Since $(s \wedge \sim s)$ is a contradiction (False),we have:$\sim P = (s \wedge r) \vee F = s \wedge r$.

The negation of $\sim s \vee (\sim r \wedge s)$ is equivalent to :

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