Negation of the statement (p vee r) Rightarro | vedclass

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Question

$\because \sim(\mathrm{A} \Rightarrow \mathrm{B})=\mathrm{A} \wedge \sim \mathrm{B}$

$	herefore \sim((\mathrm{p} \vee \mathrm{r}) \Rightarrow(\mathr

Vedclass · Accepted Answer

$\mathrm{p} \wedge \sim \mathrm{q} \wedge \sim \mathrm{r}$

Vedclass · Answer

$\because \sim(\mathrm{A} \Rightarrow \mathrm{B})=\mathrm{A} \wedge \sim \mathrm{B}$

$	herefore \sim((\mathrm{p} \vee \mathrm{r}) \Rightarrow(\mathrm{q} \vee \mathrm{r}))$

$=(\mathrm{p} \vee \mathrm{r}) \wedge(\sim \mathrm{q} \wedge \sim \mathrm{r})$

$=((\mathrm{p} \vee \mathrm{r}) \wedge(\sim \mathrm{r})) \wedge(\sim \mathrm{q})$

$=\mathrm{p} \wedge(\sim \mathrm{r}) \wedge(\sim \mathrm{q})$

Negation of the statement $(p \vee r) \Rightarrow(q \vee r)$ is :