The general solution of ${\sin ^2}\theta \sec \theta + \sqrt 3 \tan \theta = 0$ is
The general solution of ${\sin ^2}\theta \sec \theta + \sqrt 3 \tan \theta = 0$ is
- A
$\theta = n\pi + {( - 1)^{n + 1}}\frac{\pi }{3},\theta = n\pi ,n \in Z$
- B
$\theta = n\pi ,n \in Z$
- C
$\theta = n\pi + {( - 1)^{n + 1}}\frac{\pi }{3},n \in Z$
- D
$\theta = \frac{{n\pi }}{2},n \in Z$
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- [JEE MAIN 2014]
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