Find the principal solutions of the equation $\sin x=\frac{\sqrt{3}}{2}$
We know that, $\sin \frac{\pi}{3}=\frac{\sqrt{3}}{2}$ and $\sin \frac{2 \pi}{3}=\sin \left(\pi-\frac{\pi}{3}\right)=\sin \frac{\pi}{3}=\frac{\sqrt{3}}{2}$
Therefore, principal solutions are $x=\frac{\pi}{3}$ and $\frac{2 \pi}{3}$.
If $\frac{{1 - {{\tan }^2}\theta }}{{{{\sec }^2}\theta }} = \frac{1}{2}$, then the general value of $\theta $ is
If $\sqrt 3 \tan 2\theta + \sqrt 3 \tan 3\theta + \tan 2\theta \tan 3\theta = 1$, then the general value of $\theta $ is
If $2\sin \theta + \tan \theta = 0$, then the general values of $\theta $ are
If $\tan \theta + \tan 2\theta + \tan 3\theta = \tan \theta \tan 2\theta \tan 3\theta $, then the general value of $\theta $ is
The equation $\sin x + \sin y + \sin z = - 3$ for $0 \le x \le 2\pi ,$ $0 \le y \le 2\pi ,$ $0 \le z \le 2\pi $, has