If sin (A + B) =1 and cos (A - B) = frac{{sq | vedclass

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Question

(a) $\sin (A + B) = 1$ and $\cos (A - B) = \frac{{\sqrt 3 }}{2}$

$ \Rightarrow $ $A + B = \frac{\pi }{2}$ and $A - B = \frac{\pi }{6}$

$ \Righta

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${60^o},{\rm{ }}{30^o}$

Vedclass · Answer

(a) $\sin (A + B) = 1$ and $\cos (A - B) = \frac{{\sqrt 3 }}{2}$

$ \Rightarrow $ $A + B = \frac{\pi }{2}$ and $A - B = \frac{\pi }{6}$

$ \Rightarrow $ $A = \frac{\pi }{3},\,B = \frac{\pi }{6}$.

If $\sin (A + B) =1 $ and $\cos (A - B) = \frac{{\sqrt 3 }}{2},$ then the smallest positive values of $A$ and $ B$ are

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