The equation of motion of a projectile are given by $ x = 36 t\,metre$ and $2y = 96 t -9.8 t^2\, metre$. The angle of projection is
The equation of motion of a projectile are given by $ x = 36 t\,metre$ and $2y = 96 t -9.8 t^2\, metre$. The angle of projection is
- A
${\sin ^{ - 1}}\left( {\frac{4}{5}} \right)$
- B
${\sin ^{ - 1}}\left( {\frac{3}{5}} \right)$
- C
${\sin ^{ - 1}}\left( {\frac{4}{3}} \right)$
- D
${\sin ^{ - 1}}\left( {\frac{3}{4}} \right)$
Similar Questions
The range of a projectile for a given initial velocity is maximum when the angle of projection is ${45^o}$. The range will be minimum, if the angle of projection is ......... $^o$
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The range of a projectile when launched at angle $\theta$ is same as when launched at angle $2 \theta$. What is the value of $\theta$ ?
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The horizontal range is four times the maximum height attained by a projectile. The angle of projection is .......... $^o$
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- [AIEEE 2012]
What is range of the projectile particle ? Give velocity of projectile particle at maximum height.
What is range of the projectile particle ? Give velocity of projectile particle at maximum height.