(B) The time taken by the bullet to reach the target is $t = \frac{\text{distance}}{\text{speed}} = \frac{100 \, m}{1000 \, m/s} = 0.1 \, s$.During th

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(B) The time taken by the bullet to reach the target is $t = \frac{\text{distance}}{\text{speed}} = \frac{100 \, m}{1000 \, m/s} = 0.1 \, s$.During this time,the bullet undergoes a vertical downward displacement due to gravity,given by $h = \frac{1}{2}gt^2$.Substituting the values: $h = \frac{1}{2} \times 10 \, m/s^2 \times (0.1 \, s)^2 = 5 \times 0.01 \, m = 0.05 \, m = 5 \, cm$.To compensate for this downward drop,the gun must be aimed $5 \, cm$ above the target.

Class 11 Physics 3-2.Motion in Plane Horizontal Projectile Motion

Medium

$A$ bullet is fired with a speed of $1000 \, m/s$ in order to hit a target $100 \, m$ away. If $g = 10 \, m/s^2$,the gun should be aimed:

A
Directly towards the target
B
$5 \, cm$ above the target
C
$10 \, cm$ above the target
D
$15 \, cm$ above the target

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3-2.Motion in Plane

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Horizontal Projectile Motion

$A$ gun is aimed at a target in the line of its barrel. The target is released and allowed to fall under gravity at the same instant the gun is fired. The bullet will

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$A$ particle is projected with a velocity of $30\,m/s$ at an angle of $\theta_0 = \tan^{-1}(3/4)$. After $1\,s$,the particle is moving at an angle $\theta$ to the horizontal. What is the value of $\tan\theta$? (Take $g = 10\,m/s^2$)

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$A$ projectile is given an initial velocity of $(\hat{i}+2 \hat{j}) \text{ ms}^{-1}$. The equation of its path is $(g=10 \text{ ms}^{-2})$

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$A$ projectile is thrown with velocity $v$ at an angle $\theta$ with the horizontal. When the projectile is at a height equal to half of the maximum height,the vertical component of the velocity of the projectile is ...........

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$A$ body is projected from the earth at an angle of $30^{\circ}$ with the horizontal with some initial velocity. If its range is $20 \ m$,the maximum height reached by it is: (in meters)

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$A$ bullet is fired with a speed of $1000 \, m/s$ in order to hit a target $100 \, m$ away. If $g = 10 \, m/s^2$,the gun should be aimed:

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