The decay constant of the end product of a radioactive series is

  • A
    zero
  • B
    infinite
  • C
    finite (non zero)
  • D
    depends on the end product

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When a radioactive isotope ${}_{88}^{228}Ra$ decays in series by the emission of $3$ alpha particles and $1$ beta particle,the isotope finally formed is

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In the given nuclear reaction,$A, B, C, D, E$ represent:
$_{92}U^{238} \xrightarrow{\alpha} _{B}Th^{A} \xrightarrow{\beta} _{D}Pa^{C} \xrightarrow{E} _{92}U^{234}$

In a radioactive reaction $_{92}X^{232} \to _{82}Y^{204}$,the number of $\alpha$-particles emitted is:

Neutrino is a particle which $\qquad$

Alpha rays emitted from a radioactive substance are:

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