In the given nuclear reaction $A, B, C, D, E$ represents
$_{92}{U^{238}}{\xrightarrow{\alpha }_B}T{h^A}{\xrightarrow{\beta }_D}P{a^C}{\xrightarrow{E}_{92}}{U^{234}}$
In the given nuclear reaction $A, B, C, D, E$ represents
$_{92}{U^{238}}{\xrightarrow{\alpha }_B}T{h^A}{\xrightarrow{\beta }_D}P{a^C}{\xrightarrow{E}_{92}}{U^{234}}$
- A
$A = 234, B = 90, C = 234, D = 91, E = \beta $
- B
$A = 234, B = 90, C = 238, D = 94, E = \alpha $
- C
$A = 238, B = 93, C = 234, D = 91, E = \beta $
- D
$A = 234, B = 90, C = 234, D = 93, E = \alpha $
Similar Questions
Consider the following radioactive decay process
${ }_{84}^{218} A \stackrel{\alpha}{\longrightarrow} A_1 \stackrel{\beta^{-}}{\longrightarrow} A_2 \stackrel{\gamma}{\longrightarrow} A_3 \stackrel{\alpha}{\longrightarrow} A_4 \stackrel{B^{+}}{\longrightarrow} A_5 \stackrel{\gamma}{\longrightarrow} A_6$
The mass number and the atomic number $A _6$ are given by
Consider the following radioactive decay process
${ }_{84}^{218} A \stackrel{\alpha}{\longrightarrow} A_1 \stackrel{\beta^{-}}{\longrightarrow} A_2 \stackrel{\gamma}{\longrightarrow} A_3 \stackrel{\alpha}{\longrightarrow} A_4 \stackrel{B^{+}}{\longrightarrow} A_5 \stackrel{\gamma}{\longrightarrow} A_6$
The mass number and the atomic number $A _6$ are given by
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- [AIIMS 2016]
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- [AIIMS 2001]
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