The amplitude of $0$ is

Let $z$ and $w$ be complex numbers such that $\overline{z} + i\overline{w} = 0$ and $\text{arg}(zw) = \pi$. Then $\text{arg}(z)$ equals

The amplitude of $\sin \frac{\pi}{5} + i(1 - \cos \frac{\pi}{5})$ is:

Let $z$ satisfy $|z|=1$, $z=1-\bar{z}$ and $\operatorname{Im}(z) > 0$.
Statement-$I$: $z$ is a real number.
Statement-$II$: Principal argument of $z$ is $\frac{\pi}{3}$.
Then

If for complex numbers $z_1$ and $z_2$,$\arg(z_1/z_2) = 0$,then $|z_1 - z_2|$ is equal to

If ${z_1}, {z_2} \in \mathbb{C}$,then $\text{amp}\left( \frac{z_1}{\bar{z}_2} \right) = $