Stability of the species Li_2, Li_2^- and Li_ | vedclass

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Question

Correct option

(b) $\mathrm{Li}_{2}-<\mathrm{Li}_{2}^{+}<\mathrm{Li}_{2}$

Explanation:

$\mathrm{Li}_{2}(3+3=6)=\sigma 1 \mathrm{s}^{2},

Vedclass · Accepted Answer

$Li_2^- < Li_2^+ < Li_2$

Vedclass · Answer

Correct option (b) $\mathrm{Li}_{2}-<\mathrm{Li}_{2}^{+}<\mathrm{Li}_{2}$ Explanation: $\mathrm{Li}_{2}(3+3=6)=\sigma 1 \mathrm{s}^{2}, \quad \hat{\sigma} 1 \mathrm{s}^{2}, \sigma 2 \mathrm{s}^{2}$ Bond order $=\frac{N_{b}-N_{a}}{2}=\frac{4-2}{2}=1$ $\mathrm{Li}_{2}^{+}(3+3-1=5)=\sigma 1 \mathrm{s}^{2}, \dot{\sigma}^{2} 1 s^{2}, \cdot \sigma 2 s^{1}$ Bond order $=\frac{3-2}{2}=\frac{1}{2}=0.5$ Bond order $=\frac{4-3}{2}=\frac{1}{2}=0.5$ Stability order is $\mathrm{Li}_{2}>\mathrm{Li}_{2}^{+}>\mathrm{Li}_{2}^{-}$ (because Li $_{2}^{-}$ have more number of electrons in antibonding orbitals which destabilises the species).

List $I$ (Molecule Species)	List $I$ ( Property Shape )
$A$ $\mathrm{SO}_2 \mathrm{Cl}_2$	$I$ Paramagnetic
$B$ $NO$	$II$ Diamagnetic
$C$ $\mathrm{NO}_2^{-}$	$III$ Tetrahedral
$D$ $\mathrm{I}_3^{-}$	$IV$ Linear

Stability of the species $Li_2, Li_2^-$ and $Li_2^+$ increases in the order of :

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