The correct molecular orbital diagram for F_2 | vedclass

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Question

(C) The $F_2$ molecule has $18$ electrons. The molecular orbital configuration is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_

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Vedclass · Answer

(C) The $F_2$ molecule has $18$ electrons. The molecular orbital configuration is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$.In the $F_2$ molecule,the energy of the $\sigma 2p_z$ orbital is lower than the $\pi 2p_x$ and $\pi 2p_y$ orbitals due to the lack of $s-p$ mixing for elements with higher atomic numbers $(Z > 7)$.Comparing the given options with the standard molecular orbital diagram for $F_2$,option $C$ correctly represents the energy levels and electron filling.

The correct molecular orbital diagram for $F_2$ molecule in the ground state is

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