Match List $I$ with List $II$ :
List $I$ (Molecule Species) |
List $I$ ( Property Shape ) |
$A$ $\mathrm{SO}_2 \mathrm{Cl}_2$ | $I$ Paramagnetic |
$B$ $NO$ | $II$ Diamagnetic |
$C$ $\mathrm{NO}_2^{-}$ | $III$ Tetrahedral |
$D$ $\mathrm{I}_3^{-}$ | $IV$ Linear |
Choose the correct answer from the options given below :
$ A-IV, B-I, C-III, D-II $
$ A-III, B-I, C-II, D-IV$
$ A-II, B-III, C-I, D-IV$
$A-III, B-IV, C-II, D-I $
According to Molecular Orbital Theory,
($A$) $\mathrm{C}_2^{2-}$ is expected to be diamagnetic
($B$) $\mathrm{O}_2{ }^{2+}$ is expected to have a longer bond length than $\mathrm{O}_2$
($C$) $\mathrm{N}_2^{+}$and $\mathrm{N}_2^{-}$have the same bond order
($D$) $\mathrm{He}_2^{+}$has the same energy as two isolated He atoms
What bond order does $O_2^{2 - }$ have
$O_2^{2 - }$is the symbol of .. ion
In which pair, or pairs, is the stronger bond found in the first species
$(a)$ $O_2^ - ,{O_2}$ $(b)$ ${N_2},N_2^ +$ $(c)$ $NO^+, NO^-$
Which one does not exhibit paramagnetism