Simplify

(i) 2^{frac{2}{3}} cdot 2^{f | vedclass

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Question

$(i)$ $2^{\frac{2}{3}} \cdot 2^{\frac{1}{3}}=2^{\left(\frac{2}{3}+\frac{1}{3}\right)}=2^{\frac{3}{3}}=2^{1}=2$

$(ii)$ $\left(3^{\frac{1}{5}}\right)

Vedclass · Accepted Answer

Vedclass · Answer

$(i)$ $2^{\frac{2}{3}} \cdot 2^{\frac{1}{3}}=2^{\left(\frac{2}{3}+\frac{1}{3}ight)}=2^{\frac{3}{3}}=2^{1}=2$

$(ii)$ $\left(3^{\frac{1}{5}}ight)^{4}=3^{\frac{4}{5}}$

$(iii)$ $\frac{7^{\frac{1}{5}}}{7^{\frac{1}{3}}}=7^{\left(\frac{1}{5}-\frac{1}{3}ight)}=7^{\frac{3-5}{15}}=7^{\frac{-2}{15}}$

$(iv) $ $13^{\frac{1}{5}} \cdot 17^{\frac{1}{5}}=(13 	imes 17)^{\frac{1}{5}}=221^{\frac{1}{5}}$

Simplify

$(i)$ $2^{\frac{2}{3}} \cdot 2^{\frac{1}{3}}$

$(ii)$ $\left(3^{\frac{1}{5}}\right)^{4}$

$(iii)$ $\frac{7^{\frac{1}{5}}}{7^{\frac{1}{3}}}$

$(iv)$ $13^{\frac{1}{5}} \cdot 17^{\frac{1}{5}}$

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Simplify $(i)$ $2^{\frac{2}{3}} \cdot 2^{\frac{1}{3}}$ $(ii)$ $\left(3^{\frac{1}{5}}\right)^{4}$ $(iii)$ $\frac{7^{\frac{1}{5}}}{7^{\frac{1}{3}}}$ $(iv)$ $13^{\frac{1}{5}} \cdot 17^{\frac{1}{5}}$