Show that if $A \subset B$,then $(C - B) \subset (C - A)$.
(N/A) Let $A \subset B$.
To show: $(C - B) \subset (C - A)$.
Let $x \in (C - B)$.
$\Rightarrow x \in C$ and $x \notin B$.
Since $A \subset B$,if $x \notin B$,then $x \notin A$.
$\Rightarrow x \in C$ and $x \notin A$.
$\Rightarrow x \in (C - A)$.
Therefore,$(C - B) \subset (C - A)$.
To show: $(C - B) \subset (C - A)$.
Let $x \in (C - B)$.
$\Rightarrow x \in C$ and $x \notin B$.
Since $A \subset B$,if $x \notin B$,then $x \notin A$.
$\Rightarrow x \in C$ and $x \notin A$.
$\Rightarrow x \in (C - A)$.
Therefore,$(C - B) \subset (C - A)$.
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