$A$ and $B$ are two subsets of set $S$ = $\{1,2,3,4\}$ such that $A\ \cup \ B$ = $S$ , then number of ordered pair of $(A, B)$ is
If ${N_a} = \{ an:n \in N\} ,$ then ${N_3} \cap {N_4} = $
If the sets $A$ and $B$ are defined as $A = \{ (x,\,y):y = {1 \over x},\,0 \ne x \in R\} $ $B = \{ (x,y):y = - x,x \in R\} $, then
Using that for any sets $\mathrm{A}$ and $\mathrm{B},$
$A \cap(A \cup B)=A$
Sets $A$ and $B$ have $3$ and $6$ elements respectively. What can be the minimum number of elements in $A \cup B$