Show that $0.3333... =$ $0 . \overline{3}$ can be expressed in the form $\frac {p }{q }$ , where $p$ and $q$ are integers and $q \ne 0$.

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since we do not know what $0 . \overline{3}$ is , let us call it $'x'$ and so

$x=0.3333 \ldots$

Now here is where the trick comes in. Look at

$10 x=10 \times(0.333 \ldots)=3.333 \ldots$

Now,          $3.3333 \ldots=3+x,$ since $x=0.3333 \ldots$

Therefore,                  $10 x=3+x$

Solving for $x,$ we get

$9 x=3,$     i.e., $x=\frac{1}{3}$

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